SAT数学考试内容，是考生拿分的重点项目。但是想要拿到高分，我们在平时的备考中，也需要付出更多的努力，想要全面的提升SAT数学，大家还是要多做真题的练习，这样才能有效的提分。下面小编为大家整理了详细的内容，供大家参考!

1. 6 pints of a 20 percent solution of alcohol in water are mixed with 4 pints of a 10 percent alcohol in water solution. The percentage alcohol in the new solution is

A. 16

B. 15

C. 14

D. 13

E. 12

2. ASB is a quarter circle. PQRS is a rectangle with sides PQ = 8 and PS = 6. What is the length of the arc AQB ?

A. 5π

B. 10π

C. 25

D. 14

E. 28

3. If x ¤ y = (x + y)2 - (x - y)2

Then √5 ¤ √5 =

A. 0

B. 5

C. 10

D. 15

E. 20

4. Which of the following describes the relationship between A and B as shown in the pairs of numbers in the table above?

A. B = A + 4

B. B = 2A + 1

C. B = 3A - 1

D. B = A2 + 1

E. B = A2 - 1

5. The total weight of a tin and the cookies it contains is 2 pounds. After ? of the cookies are eaten, the tin and the remaining cookies weigh 0.8 pounds. What is the weight of the empty tin in pounds?

A. 0.2

B. 0.3

C. 0.4

D. 0.5

E. 0.6

6. Which of the following pairs of angles must be equal?

A. a and e only

B. a and e, and c and d only

C. c and d only

D. d and e only

E. c and d and d and e only

7. The average bonus per employee was

A. 81

B. 91

C. 100

D. 101

E. 105

8. Refer to the chart from the previous question.

If median bonus amount = m, mean bonus amount = n, and modal bonus amount = p, which of the following represents the correct ordering of m, n and p?

A. m < n < p

B. m < n = p

C. m = p

D. p < m < n

E. p = n < m

9. Which of the following is the equation of a line passing through the origin and parallel to the line 2x – y = 5?

A. 5x – y = 0

B. 2x – y = 0

C. 2x + y = 5

D. 2x + y = 0

E. x + 2y = 0

10. The graph shows a quadratic function with a minimum at (-1,1)

If f(a) = f(1), which if the following could be the value of a?

A. 2

B. 0

C. -1

D. -2

E. -3

SAT数学练习题第12套参考答案

Explanation:

Total new volume is 10 pints. The first solution contributes 0.2 x 6 pints alcohol, and the second contributes 0.1 x 4. Total alcohol = 1.6. Percentage alcohol = (1.6 / 10) x 100 = 16

Explanation:

Arc AQB is one quarter the perimeter of the circle (because angle S is a right angle).

To find the radius we need to see that the diagonal SQ of the rectangle= radius.

Now use Pythagoras to find the diagonal; 82 + 62 = r2

So r = 10 (You could have spotted that this is a 3-4-5 triangle and so saved this part of the calculation)

The length of the arc = ? 20 π = 5π

Explanation:

The strange symbol tells us what to do to x and y. We then follow these directions for the actual values for x and y given in the problem.

Hence, (2 √5)2 - (0)2 = 4.5 =20

Explanation:

You can try out the relationships using at least two pairs from the table to see whether the relationship holds. But it is relatively easy to spot that the first number squared + 1 gives the second number in each case

Explanation:

Let the weight of the empty tin = w

(2 - w) = weight of the cookies; and one quarter of the cookies weigh (2 - w)/4

One quarter of the cookies + tin = 0.8 = w + (2 - w)/4

Multiply through by 4; 3.2 = 4w + 2 - w

1.2 = 3w; w = 0.4

Explanation:

This question is testing that you know that the angle between a tangent to a circle and a chord (angle c is such an angle) is equal to the angle in the opposite segment (angle d is in the segment opposite to c in this case). Similarly, angle a is equal to angle e for the same reason.

Explanation:

To calculate the total spent in bonuses we have to multiply the bonus by the number of employees for each bonus amount: (50 x 7)+ (100 x 37)+ (150 x 4)+ (200 x 2) = 5050. Now divide by the total number of employees to find the average = 5050/50 = 101

Explanation:

The median is the middle term in the ranked series. There are 50 terms and so the median is the average of the middle two terms. Both middle terms will be 100.

Mean is 101 and mode is the most common term which is 100. Hence median and mode are equal and less than the mean.

Explanation:

First rearrange the equation into the form y = mx + c; y = 2x – 5

From this we know the slope is 2 and so the equation we are looking for must have the ‘m’ value = 2. We are also told that the equation must pass through the origin; this means that the ‘c’ value must be 0.

In B we can rearrange to get y = 2x which fulfills both requirements.