GRE数学考试部分,想要拿到高分成绩,大家在平时的复习中,还是需要对于考试的经典题目,进行详细的练习。不断的练习,才能够辅助我们更充分的备考GRE数学考试,因此下面小编为大家整理了详细的内容,供大家参考!

  题目

  1. If k is an integer and 121 < k^2 < 225,then k can have at most how many values?

  A. 3

  B. 4

  C. 5

  D. 6

  E. 7

  答案:D.

  解析:k可以是12,13,14,-12,-13,-14.

  2. Runner A ran 4/5 kilometer and Runner B ran 800 meters.

  Quantity A: The distance that A ran

  Quantity B: The distance that B ran

  A. Quantity A is greater.

  B. Quantity B is greater.

  C. The two quantities are equal.

  D. The relationship cannot be determined from the information given.

  答案:C

  解析:Quantity A=(4/5)*1000=800=Quantity B。

  3. x < y < z,

  Quantity A: (x + y + z)/3

  Quantity B: y

  A. Quantity A is greater.

  B. Quantity B is greater.

  C. The two quantities are equal.

  D. The relationship cannot be determined from the information given.

  答案:D

  解析:已知条件太少,AB大小都可以根据不同数据列出可能答案,因此无法判断准确唯一解,选D。

  4. A reading list for a humanities course consists of 10 books, of which 4 are biographies and the rest are novels. Each student is required to read a selection of 4 books from the list, including 2 or more biographies. How many selections of 4 books satisfy the requirements?

  A. 90

  B. 115

  C. 130

  D. 144

  E. 195

  答案:D

  解析:10本书中,4本biographies,6本novel。現在biographies要选2本以上。

  思路1:正面解法

  所以可能情形有bio选2本(配nov选2)+bio选3本(配nov选1本)+bio选4本(配nov选0本)。

  即(C4取2乘C6取2)+(C4取3乘C6取1)+(C4取4乘C6取0)=115

  思路2:反向解法

  用全部扣除bio选0本(配nov选4)再扣bio选1本(配nov选3)

  利用C10取4-C4取0*C6取4-C4取1*C6取3 = 210 - 15 - 80 = 115

  5. In a graduating class of 236 students, 142 took algebra and 121 took chemistry. What is the greatest possible number of students that could have taken both algebra and chemistry?

  答案:121

  解析:可能不少人会用142+121-236=27的思路来解题,但问题是least possible number,同时也没有表明只能选两门课,因此有可能还有其他課可选,因此正确答案是眼前两个交集的最大数,也就是142和121取最小数,121个学chemistry的都选了algebra。所以为121。

  以上就是关于“GRE数学满分经典题目练习”的内容,希望通过上述内容的学习,大家在接下来的GRE数学考试中有更好地发挥,预祝大家考试取得高分成绩。

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